| /* |
| * |
| * Copyright (c) 2022 Project CHIP Authors |
| * All rights reserved. |
| * |
| * Licensed under the Apache License, Version 2.0 (the "License"); |
| * you may not use this file except in compliance with the License. |
| * You may obtain a copy of the License at |
| * |
| * http://www.apache.org/licenses/LICENSE-2.0 |
| * |
| * Unless required by applicable law or agreed to in writing, software |
| * distributed under the License is distributed on an "AS IS" BASIS, |
| * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. |
| * See the License for the specific language governing permissions and |
| * limitations under the License. |
| */ |
| |
| #pragma once |
| |
| #include <app/data-model/BasicTypes.h> |
| |
| #include <type_traits> |
| |
| namespace chip { |
| namespace app { |
| namespace DataModel { |
| |
| /** |
| * IsFabricScoped checks whether the given type is fabric scoped. Non-basic types (i.e. cluster objects), should provide a |
| * static constexpr indicating whether the type is a fabric scoped struct, and basic types will never be fabric scoped. |
| * |
| * Using IsFabricScoped<X>::value without a basic type or cluster object with kIsFabricScoped will cause a compile error. This is |
| * an intended behavior to make users explicitly decide whether their cluster object is fabric-scoped or not. |
| */ |
| template <typename X> |
| class IsFabricScoped |
| { |
| private: |
| template <typename X0, decltype(std::decay_t<X0>::kIsFabricScoped) = true> |
| static constexpr bool IsFabricScopedClusterObject() |
| { |
| return std::decay_t<X0>::kIsFabricScoped; |
| } |
| |
| template <typename X0, std::enable_if_t<IsBasicType<std::decay_t<X0>>::value, bool> = true> |
| static constexpr bool IsFabricScopedClusterObject() |
| { |
| return false; |
| } |
| |
| public: |
| static constexpr bool value = IsFabricScopedClusterObject<X>(); |
| }; |
| |
| } // namespace DataModel |
| } // namespace app |
| } // namespace chip |