gen_syscalls.py: do not output data to stdout
There's no particularly good reason to have one kind of
output from this script to be sent to stdout instead of
a filename specified by parameter, and it makes it
annoying to add debug print() statements.
Signed-off-by: Andrew Boie <andrew.p.boie@intel.com>
diff --git a/scripts/gen_syscalls.py b/scripts/gen_syscalls.py
index 8b74a1d..b1a9f0e 100755
--- a/scripts/gen_syscalls.py
+++ b/scripts/gen_syscalls.py
@@ -168,6 +168,8 @@
help="Read syscall information from json file")
parser.add_argument("-d", "--syscall-dispatch", required=True,
help="output C system call dispatch table file")
+ parser.add_argument("-l", "--syscall-list", required=True,
+ help="output C system call list header")
parser.add_argument("-o", "--base-output", required=True,
help="Base output directory for syscall macro headers")
args = parser.parse_args()
@@ -206,7 +208,8 @@
ids.sort()
ids.extend(["K_SYSCALL_BAD", "K_SYSCALL_LIMIT"])
handler_defines = "".join([handler_template % name for name in handlers])
- sys.stdout.write(list_template % (",\n\t".join(ids), handler_defines))
+ with open(args.syscall_list, "w") as fp:
+ fp.write(list_template % (",\n\t".join(ids), handler_defines))
os.makedirs(args.base_output, exist_ok=True)
for fn, invo_list in invocations.items():
