| # Copyright 2019 The Bazel Authors. All rights reserved. | |
| # | |
| # Licensed under the Apache License, Version 2.0 (the "License"); | |
| # you may not use this file except in compliance with the License. | |
| # You may obtain a copy of the License at | |
| # | |
| # http://www.apache.org/licenses/LICENSE-2.0 | |
| # | |
| # Unless required by applicable law or agreed to in writing, software | |
| # distributed under the License is distributed on an "AS IS" BASIS, | |
| # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | |
| # See the License for the specific language governing permissions and | |
| # limitations under the License. | |
| # We'd like to alias the runfiles target @bazel_tools//tools/python/runfiles. | |
| # However, we need its source file to exist in the runfiles tree under this | |
| # repo's name, so that it can be imported as | |
| # | |
| # from rules_python.python.runfiles import runfiles | |
| # | |
| # in user code. This requires either adding a symlink to runfiles or copying | |
| # the file with an action. | |
| # | |
| # Both solutions are made more difficult by the fact that runfiles.py is not | |
| # directly exported by its package. We could try to get a handle on its File | |
| # object by unpacking the runfiles target's providers, but this seems hacky | |
| # and is probably more effort than it's worth. Also, it's not trivial to copy | |
| # files in a cross-platform (i.e. Windows-friendly) way. | |
| # | |
| # So instead, we just vendor in runfiles.py here. | |
| load("//python:defs.bzl", "py_library") | |
| filegroup( | |
| name = "distribution", | |
| srcs = glob(["**"]), | |
| visibility = ["//python:__pkg__"], | |
| ) | |
| py_library( | |
| name = "runfiles", | |
| srcs = ["runfiles.py"], | |
| visibility = ["//visibility:public"], | |
| ) |